calculate the number of atoms present in 1.4 gram of two molecules of Nitrogen
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Number of moles = given weight/ molecular weight
n= w/m
n= 1.4/14
1 mole of N2 molecule contain = 1.4/14×6.023×10^23
=6.023×10^22
1 mole of N2 molecule contains 6.023×10^22 molecules of N2
And each N2 molecule contains two atoms of N .
Show the number of atoms is 2×6.023×10^22 .
n= w/m
n= 1.4/14
1 mole of N2 molecule contain = 1.4/14×6.023×10^23
=6.023×10^22
1 mole of N2 molecule contains 6.023×10^22 molecules of N2
And each N2 molecule contains two atoms of N .
Show the number of atoms is 2×6.023×10^22 .
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