Question

calculate the number of atoms present in 24g of helium . (he =4u) ​

Answer 1

Explanation:

Number of mole n=w/m

n=24/4=6

Number of atom =6×6.022×10^23

=36.132×10^23

Answer 2

Answer:

1 mole of Helium contains 6.023×10^23 atoms. 1 mole of Helium = 4 gm. So, 20 gm of Helium contains — (20÷4)×6.023×10^23 atoms =

3.011×10^24 atoms.

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