Question

From the roof of a school, the angle of elevation to the top of a building is 23 degrees and the angle of depression to the bottom of this building is 52 degrees. The distance between the school and this building is 35m. Determine the height of the building to the nearest tenth of a metre.

Answer 1

Answer:

the answer of the question is 262.5 (appox.)

Answer 2

Answer:

Height of the building is 29.74 m

Step-by-step explanation:

Given by the question,

We know that,

Angle elevation of the top of a building is = 23°

Angle depression to the bottom is = 52°

Now,

The distance between school and the building is = 35 m

So,

$tan 23= \frac{x}{35}\\ x = 35\times tan23\\x = 14.85$

And,

$tan 52 = \frac{x+h}{35} \\35\times tan 52 = x+h\\x+h = 44.79$

On putting the value of x in the above equation we get,

$14.85+h = 44.79\\ h=29.94$

Therefore, the height of the building to nearest tenth is 29.94 m

Hence, the correct answer is 29.74 m.