Chemistry, asked by jianaphilip2004, 11 months ago

calculate the number of atoms present in 284g of p4

Answers

Answered by sreeh123flyback
1

Answer:

13.7858×10^23 atoms of P4

molar mass of 1 P atom is 31g/mol

so molar mass of 4 P atom is 31×4=124g/mol

no moles of Phosphorus is

mass /molar mass =284/124=2.290mol

so number of atoms of P4 is 2.290 moles

so 1 mol =6.02×10^23 particles

2.290 mol = 2.290×6.02×10^23 atoms

=13.7858×10^23 atoms

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