calculate the number of atoms present in 284g of p4
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Answer:
13.7858×10^23 atoms of P4
molar mass of 1 P atom is 31g/mol
so molar mass of 4 P atom is 31×4=124g/mol
no moles of Phosphorus is
mass /molar mass =284/124=2.290mol
so number of atoms of P4 is 2.290 moles
so 1 mol =6.02×10^23 particles
2.290 mol = 2.290×6.02×10^23 atoms
=13.7858×10^23 atoms
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