Question

calculate the number of atoms present in 5.6lt.of a monoatomic gas​

Answer 1

Answer:

5.6l of O2 means we have 0.25 moles of O2. and as 1 molecule of O2 has 2 atoms, so, 1.50575*10^23 molecules will have 2*1.50575*10^23 atoms=3.0115*10^23 atoms of O. One mole of any gas occupies 22.4L of volume at NTP or STP and one mole of a gas contains Avogadro Number of molecules at NTP ie 6.022×10raised to 23.

Answer 2

One mole of a gas contains 6.023 x 10^23 constituent particles of the gas and occupies 22.4 L volume. Therefore, 5.6 L is occupied by 0.25 moles of a gas, which will therefore contain 0.25 x 6.023 x 10^23 particles. 1.50575 * 10^23 molecules of Oxygen gas in 5.6 L