calculate the number of atoms present in 6.4 g of sulphur dioxide
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no of moles =6.4/64=0.1
no of atoms =3×0.1×6.022×10^23
= 1.8×10^23
no of atoms =3×0.1×6.022×10^23
= 1.8×10^23
MaheshwarTryme:
there are only 3 atoms in SO2
Answered by
0
18.069*10^22 is the total no of atoms
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