Calculate the number of atoms present in each of the sample? (Atomic mass=14 O=16)
1 .42 g Nitrogen
2. 80 g Oxygen.
Answers
Answered by
1
80 g Oxygen.
No. of GAM= 80/16 =5GAM
No. of atoms =5×6.022×10²³
Answered by
1
42 g Nitrogen,
No. of GAM =1442= 3
No. of atoms =3×6.022×1023=18.066×1023
Similar questions