calculate the number of chlorine ions in 75g of aluminum chloride?
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Explanation:
in AlCl3 Wt. of Al is 27gm and that of chlorine is 106.5gm
so in 133.5gm of AlCl3 have 106.5gm of Cl
therefore, 75gm of AlCl3 will have 59.83gm of Cl
For finding no. of ions,
no. of moles of Cl*Avogadro's no. * no. of Cl in AlCl3
= 59.83/35.5 * 6.02*10²³ * 3
=30.43*10²³
or 5.05*Nà
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