calculate the number of electrons passing a point in the wire in 1min when the current is 5.0uA
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i = nQ / t
n = it / Q
= (5.0 × 10⁻⁶ Ampere × 1 × 60 second) / (1.6 × 10⁻¹⁹ Coulomb)
= 1.875 × 10¹⁵
Number of electrons passing is 1.875 × 10¹⁵
n = it / Q
= (5.0 × 10⁻⁶ Ampere × 1 × 60 second) / (1.6 × 10⁻¹⁹ Coulomb)
= 1.875 × 10¹⁵
Number of electrons passing is 1.875 × 10¹⁵
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