Calculate the number of electrons present in 0.01C of charge?
Answers
Answered by
0
Q=0.01C
Q=-ne
0.01=n* 1.6*10^-19
0.01/-1.6*10^-19= n
n=-1.6*10^-17
Attachments:

Answered by
0
Answer:6.24 x 10^16
Explanation:
1C = 6.24x10^18
∴0.01 = x
by unitary method
0.01x6.24x10^18
=6.24 x 10^16
Similar questions
English,
7 months ago
History,
7 months ago
Science,
7 months ago
CBSE BOARD XII,
1 year ago
Math,
1 year ago