Question

Calculate the number of electrons present in 0.01C of charge?

Answer 1

Explanation:

Q=ne

Q=0.01, e=1.6×10^ -19

0.01=n×1.6×10^ -19

1 ×10^ -2 =1.6×10^-19 ×n

n=1×10^-2/1.6×10^-19

n=1×10^-2×10^+19/1.6

n=1×10^17/1.6

n=1×10^18/16

n=0.625×10^17

n=625×10^14