calculate the number of electrons present in -1.6 into 10 raise to power minus 6 full on charge
Answers
Answered by
3
Given,
Charge= 1.6× 10^-6=Qe(let)
the toal charge due to N electrons is
Qe = N*e { e is the fundamental charge 1.6× =1.6*10-19}
1.6×10^-6 = 1.6*10-19 ×N(no. of electrons)
N= 10¹³ electrons
hope you understand!!!!
Charge= 1.6× 10^-6=Qe(let)
the toal charge due to N electrons is
Qe = N*e { e is the fundamental charge 1.6× =1.6*10-19}
1.6×10^-6 = 1.6*10-19 ×N(no. of electrons)
N= 10¹³ electrons
hope you understand!!!!
Attachments:
Similar questions