Question

three no.are in a.p. whose sum is 33 and product is 792, then smallest no. from these no.is-

Answer 1

it is clear that middle no is 33/3=11,then by 2nd equation we get 121-d*d=72 ,so d= 7 there4 smallest no. 11-7=4.

Answer 2

Answer:

Let a-d, a, a+d be the 3 numbers in AP.

Sum = a-d+a+a+d = 33

3a = 33

a = 11

Product, (a-d)a(a+d) = 792

(11-d)11(11+d) = 792

121-d² = 792/11

121-d² = 72

121-72 = d2

So d² = 49

d = ±7

So 4, 11, 18 or 18, 11, 4 are the numbers.

Smallest number is 4.