Question

Calculate the number of electrons that flow through a conductor

in 2 second to constitute a current of 1 ampere.​

Answer 1

Answer:

1 ampere current flows through a conductor ,when a charge of one coulomb flows through it in 1 second. Thus 6.25 x 10 18 electrons flowing per second constitute 1ampere current.

Hope it helps you.

Please mark it as brainliest.

Answer 2

Answer:

$\huge\star\underbrace{\mathtt\red{⫷❥ᴀ᭄} \mathtt\green{n~ }\mathtt\blue{ §} \mathtt\purple{₩}\mathtt\orange{Σ} \mathtt\pink{R⫸}}\star\:$

Explanation:

$\huge{\underline{\underline{Given→}}}$

→Current=>1A

→Time=>2s

→Charge(Q)=?

$\boxed{→I=\dfrac{Q}{T}=\dfrac{Charge}{Time}}$

$\huge{\underline{\underline{To Find→}}}$

Number of electrons flowing through it.

So let the numbers of electrons be ‘n’

$\boxed{→n=\dfrac{Q}{e}}$

$\huge{\underline{\underline{Answer→}}}$

$\boxed{I=\dfrac{Q}{T}}$

→1A=Q/2

→Q=1x2

→Q=2C.

$\boxed{n=\dfrac{Q}{e}}$

$→$ As e= $1.6\times10^{-19}C$(Charge on electron).

$→n=\dfrac{Q}{e}$

$→n=\dfrac{2}{1.6\times10^{-19}}$

$→n=2\times\dfrac{10^{19}}{1.6}$

$→n=2\times\dfrac{10^{20}}{16}$

$→n=\dfrac{10^{20}}{8}$

$→n=10^{19}\times\dfrac{10}{8}$

$→n=10^{19}\times\dfrac{5}{4}$

$→n=1.25\times10^{19}$

${\boxed{\boxed{→n=1.25\times10^{19}}}}$

☞So the number of electrons flowing through it are $1.25\times10^{19}$

HOPE IT HELPS.