Calculate the number of electrons that flows per second to constitute a current of one ampere. Charge on an electrons is 1.6*10 raise to power -19 coloumb
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36
Your answer ----
Given, time t = 1s current I = 1A
we know that
I = Q/t
=> Q = I × t
=> Q = 1 × 1 = 1
We know that
Q = ne
where ,
Q = charge
n = number of electron
e = elementary charge ( = 1.6 × 10^-19 )
put the values , we get
1 = n × 1.6 × 10^-19
=> n = 1/(1.6×10^-19)
=> n = 6.25 × 10^18 electrons
Hence, 6.25 × 10^18 electrons flows per second to constitute a current of one ampere.
【 Hope it helps you 】
Given, time t = 1s current I = 1A
we know that
I = Q/t
=> Q = I × t
=> Q = 1 × 1 = 1
We know that
Q = ne
where ,
Q = charge
n = number of electron
e = elementary charge ( = 1.6 × 10^-19 )
put the values , we get
1 = n × 1.6 × 10^-19
=> n = 1/(1.6×10^-19)
=> n = 6.25 × 10^18 electrons
Hence, 6.25 × 10^18 electrons flows per second to constitute a current of one ampere.
【 Hope it helps you 】
varnikasaroch:
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Answered by
13
no of electrons= Q/E
= 1/ 1.6* 10 raise to power - 19
=10/16*10 raise to power -19
then 10 raise to power -19 will go up and then 19 will become positive
=10* 10 raise to power 19 / 16
= as 10/16 = 0.625 * 10 raise to power 19
now we have decreased the power to 18 as we have shifted the decimal.
= 6.25* 10 raise to power 18
Answer is 6.25* 10 raise to power 18
= 1/ 1.6* 10 raise to power - 19
=10/16*10 raise to power -19
then 10 raise to power -19 will go up and then 19 will become positive
=10* 10 raise to power 19 / 16
= as 10/16 = 0.625 * 10 raise to power 19
now we have decreased the power to 18 as we have shifted the decimal.
= 6.25* 10 raise to power 18
Answer is 6.25* 10 raise to power 18
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