Calculate the number of H-atoms in 128g of nitrozene (N2H4)
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The oxidation state of two nitrogen in hydrazine is −4 as four hydrogen atoms have =1 each.
Therefore, 1 nitrogen has oxidation state of −2.
When hydrazine containing two nitrogen atoms loses 10 electrons, the oxidation state of two nitrogen changes from −4 to +6.
Therefore, the oxidation state changes from −2+5=+3 per nitrogen atom.
Option C is correct.
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