Question

calculate the number of hydrogen and oxygen molecules in a solution prepared by 45g of glucose in 36g of water .

Answer 1

Answer:

15h,20o2

Explanation:

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Answer 2

Answer:

Answer: oxygen molecules - 1.052x 10^24

Hydrogen molecules - 2.1 x 10^24

Explanation: No. of molecules of gulcose in 45gm= 45/180*6.022*10^23 = 1.50 *10^23

No of molecules of O2 = 3* 1.50*10^23= 4.5*10^23

No of hydrogen molecules = 6*1.50*10^23 = 9*10^23

In H2O of 36GM.

No. Of molecules of H20 36/18*6.022*10^23

No. Of hydrogen molecules = 12.04 * 10^23

No. Of oxygen = 6.022*10^23

Total oxygen molecules = (4.5+6.022)*10^23= 1.052*10^24

Total hydrogen molecules=( 12.04+9)*10^23= 2.10*10^24