Question

(x -bc)/(d+c)+(x-ca)/(c+a)+(x-ab)/(a+b)=a+b+c​

Answer 1

Answer:

Step-by-step explanation:options given in the question will be                                                        (A).a^2+b^2+c^2     (B).a(a+b+c)     (C). (a+b)(b+c)     (D).ab+bc+ca

SOLUTION :

by option test :  the ans will be option (D)

EXPLANATION:   put x = ab+bc+ca that is taken from the option

now, ab+bc+ca-bc/b+c   +    ab+bc+ca-ca/c+a    +    ab+bc+ca-ab/a+b =a+b+c

ab+ca/b+c  +   ab+bc/c+a   +   bc+ca/a+b   =  a+b+c

ab+ca+ab+bc+bc+ca/b+c+c+a+a+b  =  a+b+c  

2ab+2ca+2bc/2b+2c+2a  =   a+b+c

2(ab+ca+bc)/2(a+c+b)  =   a+b+c

a+b+c  =   a+b+c

Therefore both left and right side becomes equal.

                                                                                 

Answer 2

Answer:

x = ab + bc +ac

Step-by-step explanation:

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