Question

calculate the number of iron atoms in a peace of iron weighing 2.8 g ​

Answer 1

Explanation:

Given that, weight of iron =2.8 g

Given that, weight of iron =2.8 gAtomic mass= 56

Given that, weight of iron =2.8 gAtomic mass= 56moles of iron= \dfrac{\text{wt. of iron}}{\text{atomic mass}}=\dfrac{2.8}{56}=0.05\ moles=

Given that, weight of iron =2.8 gAtomic mass= 56moles of iron= \dfrac{\text{wt. of iron}}{\text{atomic mass}}=\dfrac{2.8}{56}=0.05\ moles= atomic mass

Given that, weight of iron =2.8 gAtomic mass= 56moles of iron= \dfrac{\text{wt. of iron}}{\text{atomic mass}}=\dfrac{2.8}{56}=0.05\ moles= atomic masswt. of iron

Given that, weight of iron =2.8 gAtomic mass= 56moles of iron= \dfrac{\text{wt. of iron}}{\text{atomic mass}}=\dfrac{2.8}{56}=0.05\ moles= atomic masswt. of iron

Given that, weight of iron =2.8 gAtomic mass= 56moles of iron= \dfrac{\text{wt. of iron}}{\text{atomic mass}}=\dfrac{2.8}{56}=0.05\ moles= atomic masswt. of iron =

Given that, weight of iron =2.8 gAtomic mass= 56moles of iron= \dfrac{\text{wt. of iron}}{\text{atomic mass}}=\dfrac{2.8}{56}=0.05\ moles= atomic masswt. of iron = 56

Given that, weight of iron =2.8 gAtomic mass= 56moles of iron= \dfrac{\text{wt. of iron}}{\text{atomic mass}}=\dfrac{2.8}{56}=0.05\ moles= atomic masswt. of iron = 562.8

Given that, weight of iron =2.8 gAtomic mass= 56moles of iron= \dfrac{\text{wt. of iron}}{\text{atomic mass}}=\dfrac{2.8}{56}=0.05\ moles= atomic masswt. of iron = 562.8

Given that, weight of iron =2.8 gAtomic mass= 56moles of iron= \dfrac{\text{wt. of iron}}{\text{atomic mass}}=\dfrac{2.8}{56}=0.05\ moles= atomic masswt. of iron = 562.8 =0.05 moles

Given that, weight of iron =2.8 gAtomic mass= 56moles of iron= \dfrac{\text{wt. of iron}}{\text{atomic mass}}=\dfrac{2.8}{56}=0.05\ moles= atomic masswt. of iron = 562.8 =0.05 moles1 mole = 6.022 \times 10^{23}\ atoms=6.022×10

Given that, weight of iron =2.8 gAtomic mass= 56moles of iron= \dfrac{\text{wt. of iron}}{\text{atomic mass}}=\dfrac{2.8}{56}=0.05\ moles= atomic masswt. of iron = 562.8 =0.05 moles1 mole = 6.022 \times 10^{23}\ atoms=6.022×10 23

Given that, weight of iron =2.8 gAtomic mass= 56moles of iron= \dfrac{\text{wt. of iron}}{\text{atomic mass}}=\dfrac{2.8}{56}=0.05\ moles= atomic masswt. of iron = 562.8 =0.05 moles1 mole = 6.022 \times 10^{23}\ atoms=6.022×10 23 atoms

Given that, weight of iron =2.8 gAtomic mass= 56moles of iron= \dfrac{\text{wt. of iron}}{\text{atomic mass}}=\dfrac{2.8}{56}=0.05\ moles= atomic masswt. of iron = 562.8 =0.05 moles1 mole = 6.022 \times 10^{23}\ atoms=6.022×10 23 atoms0.05 moles = 6.022 \times 0.05 \t

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