Question

Calculate the number of kj of heat necessary to raise the temperature of 60 g of aluminium from 35°C to 55°C. Molar heat capacity of Al is 24 J mol-1 K-1.
please solve​

Answer 1

Answer : -

No. of moles of Al (m) = (60g)/(27 g mol-1)

= 2.22 mol

•Molar heat capacity (C) = 24 J mol-1 K-1.

•Rise in temperature (∆T) = 55 – 35 = 20°C = 20 K

•Heat evolved (q) = C x m x T

By calculating ,

= (24 ) x (2.22) x (20 K)

= 1065.6 J

= 1.067 kj

Answer 2

Answer:

Explanation:

(m) = (60g) ÷ (27 g moles ^-1)

= 2.22moles

Here, (C) = 24 J mol^-1 K^-1

Here, (∆T) = 55° – 35° = 20°C = 20° K

Here, (q) = C x m x T

Then,

= (24 ) x (2.22) x (20 k)

= >>>1065.6 Joules

Hope it will help you