Chemistry, asked by pradu5697, 9 months ago

Calculate the number of lone pairs on the central atom in if5 and xef2 and predict the shape on the basis of vsepr theory

Answers

Answered by nashwakvt5

Answer:--1.IF5

central atom=I

lone pairs=1

shape=square pyramidal geometry

--2.xeF2

central atom=xe

lone pairs=3

shape=linear geometry

Explanation:in IF5 there are 5 bond pairs and one lone pair around central atom I.

-as per VSEPR theory, these bond stay as far as possible to decrease their mutual repulsion.

-that's why, they arrange in octahedral fashion. but, there is a lone pair in corner and the actual geometry of this molecule turns into square pyramidal.

--in xef2, there are 2 bond pairs and 3 lone pairs.

-as per VSPER theory they stay as far as possible to decrease mutual repulsion so they have to attain trigonal bipyramidal fashion.

-but ,to avoid lone pair -lonenpair 90° interactions, the 3 lone pairs occupy equatorial positions while there 2 bond Pairs occupy at axial positions.

-then the geometry turns to linear.

Answered by indhirareddy224

Answer: