Calculate the number of lone pairs on the central atom in if5 and xef2 and predict the shape on the basis of vsepr theory
Answers
Answer:--1.IF5
central atom=I
lone pairs=1
shape=square pyramidal geometry
--2.xeF2
central atom=xe
lone pairs=3
shape=linear geometry
Explanation:in IF5 there are 5 bond pairs and one lone pair around central atom I.
-as per VSEPR theory, these bond stay as far as possible to decrease their mutual repulsion.
-that's why, they arrange in octahedral fashion. but, there is a lone pair in corner and the actual geometry of this molecule turns into square pyramidal.
--in xef2, there are 2 bond pairs and 3 lone pairs.
-as per VSPER theory they stay as far as possible to decrease mutual repulsion so they have to attain trigonal bipyramidal fashion.
-but ,to avoid lone pair -lonenpair 90° interactions, the 3 lone pairs occupy equatorial positions while there 2 bond Pairs occupy at axial positions.
-then the geometry turns to linear.
Answer:
Answer:--1.IF5
central atom=I
lone pairs=1
shape=square pyramidal geometry
--2.xeF2
central atom=xe
lone pairs=3
shape=linear geometry
Explanation: