Question

Calculate the number of molecules and number of atoms present in 1g of Nitrogen​

Answer 1

Refer to the Attachment ✌️

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Answer 2

Solution :

Molar mass of nitrogen gas:

$\implies$ $\sf{N_{2}}$ * 14

$\implies$ 2 * 14

$\implies$ 28 u

Mass of nitrogen gas = 1 g

We know that:

$\boxed{\sf{No.\:of\:moles = \frac{Given\:mass}{Molar\:mass}}}$

$\implies$ 1 / 28

$\implies$ 0.035 moles

Now,

The number of molecules:

$\implies$ 0.035 * 6.022 * 10^23

$\implies$ 0.21077 * 10^23

$\implies$ 2.1 × 10^22

Hence:

The number of molecules in 1g of Nitrogen gas is 2.1 × 10^22.

Now,

We know that:

$\boxed{\sf{No.\:of\:particles = \frac{No.\:of\:moles}{Avogadro's\:no.}}}$

$\implies$ 0.035 / 6.022 × 10^23

$\implies$ 0.00581 × 10^-23 atoms

Hence:

0.00581 × 10^-23 atoms are present in 1 g of nitrogen.