Question

calculate the number of molecules in 34.2 grams of cane sugar c12 h22 o11​

Answer 1

ANSWER:

Given:

Mass of cane sugar ($C_{12}H_{22}O_{11}$) = 34.2 grams.

Solution:

Gram molar mass of $C_{12}H_{22}O_{11}$ = 12 × 12 + 22 × 1 + 16 × 11 = 342.0 gram,

342.0 gram $C_{12} H_{22} O_{11}$ contains 6.022 × $10^{23}$ molecules

∵ 34.2 gram of $C_{12} H_{22} O_{11}$ contains $\frac{34.2}{342}$  × 6.022 × $10^{23}$ = 6.022 × $10^{22}$ molecules