Question

Calculate the number of molecules of methane and number of C and H atoms in 25 g of methane.

Full solution required. ​

Answer 1

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HERE'S YOUR....

HIGH RATED GABRU---HARSH ♦️♦️♦️♦️♦️♦️♦️♦️♦️♦️

Mol.weight of CH4=16CH4=16

16gCH4=N16gCH4=Nmolecules

25gCH4=6.023×1023×251625gCH4=6.023×1023×2516molecules

⇒9.41×1023⇒9.41×1023 molecules

16gCH4=NatomofC16gCH4=NatomofC

25gCH4=6.023×1023×251625gCH4=6.023×1023×2516atoms of C

⇒9.41×1023⇒9.41×1023 atoms of C

Also,

16gCH4=N16gCH4=Natoms of H

25gCH4=4×25×6.023×10231625gCH4=4×25×6.023×102316atoms of H

⇒3.764×1024⇒3.764×1024atoms of H

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Answer 2

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9.41×10^23
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We know very well that Methane = CH4

to find=

the number of molecules of Methane in 25 g of Methane.


number of atoms of C and number of atoms of H

Number of atoms of C = 9.41 × 10^23

Number of atoms of H = 3.764 × 10^24

The concept of Avogadro constant is used in this all .

Let us know what is. Avogadro's constant?

One mole is a collection of 6.022 ×10²³ particles, be the atoms, molecules, ions , electrons, photons or any other things.
This value of 6.022 ×10²³ is the Avogadro's number.