Question

calculate the number of molecules of NH3 gas present in 448 ml of it at STP

Answer 1

no of molecules=(448/22400)×6.02×10^23=0.1204×10^23

Answer 2

Answer:-

Oxygen = 448 ml

moles produced =O2

22400 =448

=0.02moles

→2KCl+3O 2

POAC in Oxygen Atoms

Oxygen in KClO3 oxygen in O2

KClO3) = 3 moles of O2

(=3×0.022× 122.5x)

=0.06

x=0.03×122.5

x=3.675g

Answer=3.675g