if a square + b square + c square = 20 and AB+ BC + CA is equal to 3 find a + b + c
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a square +b square+c square =20
ab+bc+ca=3
then (a+b+c) whole square =a square +b square +c square +2(ab+bc+ca)=20+2(3)=26
So, a+b+c=
ab+bc+ca=3
then (a+b+c) whole square =a square +b square +c square +2(ab+bc+ca)=20+2(3)=26
So, a+b+c=
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your answer is√ 26. take a look at picture.
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