Question

Calculate the number of molecules of oxygen gas that occupies a volume of 224ml at 273K atom pressure

Answer 1

Answer:

1.66×10^-23

Explanation:

PV=nrt n=m/M

224/0.0821× 273 = n

n= 9.99 mole

n=m /M

10×32 =m

m=320g

for molecule.

10÷ 6.02×10^23

1.66×10^-23 is answer.