Question

Calculate the number of molecules of sulphur ( S8) (8 is subscripted) present in 16g of solid sulphur

Answer 1

Molar mass of S8 = 32 x 8 = 256 g
Molar mass contains Avogadro's number of particles = 6.02 x 10∧23

If 256 g contains = 6.02 x 10∧23
∴ 16 g = (16 x 6.02 x 10∧23) ÷ 256
           = 3.763 x 10∧22 Molecules

Answer 2

$<b>$☺ Hello mate__ ❤

◾◾here is your answer.

1 mole of solid sulphur (S8)

= 8 × 32g

= 256g

i.e., 256g of solid sulphur contains

= 6.022 × 10^23 molecules

Then, 16g of solid sulpur contains

(6.022×10^23 /256 )16 molecules

= 3.76 × 10^22 molecules (approx)

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I hope, this will help you.☺

Thank you______❤

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