Question

calculate the number of molecules of sulphur (S8) present in 512 g of solid sulphur

Answer 1

mass of 1 mole of  (S8) = 8 × 32 = 256g

256g of (S8) contains 6 × $10^{23}$ molecules

∴ 512 g of (S8) contains = 6 × $10^{23}$/256 × 512

                                       = 12 × $10^{23}$ molecules

Answer 2

$<b>$☺ Hello mate__ ❤

◾◾here is your answer.

1 mole of solid sulphur (S8)

= 8 × 32g

= 256g

i.e., 256g of solid sulphur contains

= 6.022 × 10^23 molecules

Then, 512g of solid sulpur contains

(6.022×10^23 /256 )512 molecules

= 12× 10^23molecules (approx)

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I hope, this will help you.☺

Thank you______❤

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