calculate the number of molecules present in 0.02339g of chloroform (CHCI3) [ H=1u , c= 12u , Ci= 35.5u]
Answers
Answered by
2
Explanation:
no of moles=wt in gm/mol mass
=0.02339/12+1+106.5
=0.02339/119.5
=0.000195
no of moles=no of molecule/avagadros number
=no.of molecule =no of moles×Avagadro number
=0.000195×6.023×10^23...
hope it helps..
Answered by
0
Answer:
d GN vhfuefjdyyeddyedvdye652*'52*++4522fyjfeuudhsey
Similar questions