Question

calculate the number of molecules present in 27 g of H2O and 16 g of S8

Answer 1

Weight of H₂O = 27g

molecular weight of H₂O = 18g/mol

so, number of moles of H₂O = 27/18 = 3/2 = 1.5

number of molecules = number of mole × Avogadro’s number

= 1.5 × 6.023 × 10²³ = 90.345 × 10²³ = 9.0345 × 10²³

Similarly, weight of S₈ = 16g

Molecular weight of S₈ = 32 * 8 = 256g/mol

so, number of mole of S₈ = 16/256 = 1/16

Number of molecule of S₈ = number of mole of S₈ × Avogadro number

  = 1/16 × 6.023 × 10²³

=0.376 × 10²³ = 3.76 × 10²²  

Answer 2

Here u go

Weight of H2O=27g

Molecular weight of water=1×2+16=18u

That is 18g/mol

So the number of moles of water in 27gms is=27÷18=3÷2=1.5

Number of molecules=Number of mole × avargadro number

1.5×6.023×10²³=90.345×10²³=

9.0345×10.22gm is the answer

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