Question

Calculate the number of molecules present in 34.2 grams of cane sugar

Answer 1

molecular weight of C12H22O11 = 12*12+1*22+16*11= 144+22+176=342.

so, 342g of cane sugar contains 6.023*10^23 molecules,

then 34.2g of cane sugar contains 6.023*10^23/342*34.2=6.023molecules.

therefore 6.023is the answer.