Question

calculate the number of molecules present in a spherical drop of water having a radius 1mm it density of water is 1gcm^3​

Answer 1

Answer:

Radius of drop = 1mm= 10-1cm

density = 1gm/cm3

So, Volume of the drop = 4/3π r3 = 4/3 x 22/7 x(10-1)3 =88/21 x10-3 = 4.19 x10-3 ml

Now, mass = density x volume =1x 4.19 x10-3 =4.19 x10-3 gm

Since 1 mole of water contains = 18 gm = 6.022 x 1023 molecules of water

So, 4.19 x10-3 gm water will have = 6.022 x 1023 /18 x4.19 x10-3 = 1.4 x 1020 molecules of water.

Answer 2

Answer:

So, here is your answer which is 1.4×10^20 molecules.

Hope it helps to you.