Question

Calculate the number of molecules present in the 36g water

Answer 1

Explanation:

It is equal to Avogadro's number (NA), namely 6.022 x1023. If we have one mole of water, then we know that it will have a mass of 2 grams (for 2 moles of H atoms) + 16 grams (for one mole O atom) = 18 grams. Since we only have 0.001 grams, that means that we have NA * (0.001/18) = 3.35*1019 molecules of water!

Answer 2

Answer:

12.046*10^23 molecules of H20

Explanation:

The moleculer weight of H20=18

Thus, 18gms of H20= 1 mole of H20

36gms of H20= 2 mole of H20

1 Mole of H20=6.023*10^23

2 mole of H20=2*6.023*10^23

12.046*10^23.

PLEASE MARK ME AS A BRAINLIEST

HOPE IT WILL HELP YOU. ❤❤