Question

Calculate the number of moles and molecules of acetic acid present in 22 g of it.

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Answer 1

Explanation:

To find : the number of moles and molecules present in 22 g of acetic acid

Solution :

molecular mass of CH3COOH =(2×atomic mass of C)+(4× atomic mass of H)+(2×atomic mass of O)

=(2× 12u)+(4×1u)+(2×16u)

=60u

Number of moles = mass/ molar mass

= 22/60

=0.3667 mol

Number of molecules = Number of moles × Avogadro's constant

=0.3667 × 6.022×1023 molecules

=2.208×1023 molecules