Question

Calculate the number of moles in 5.6 Fe

Answer 1

Atomic mass of nitrogen = 14 u
Molar mass of ${{N}{2}}$ = 2 X 14 = 28 g/mol
(i) Number of moles of nitrogen = Given mass / molar mass = 5.6 / 28 = 0.2 mol
(ii) Number of mole of nitrogen = Given mass / molar mass x Avagadro number = m/M x ${{N}{A}}$
n = 5.6 / 28 x 6.022 x ${10}^{23}$ = 1.0244 x ${10}^{23}$ molecules.
(iii) One molecule of nitrogen contains two atoms of nitrogen .
Number of nitrogen = 2 x number of nitrogen molecules= 2 x 1.2044 x ${10}^{23}$ = 2.4088 x ${10}^{23}$ plz say thanks