Question

Calculate the number of moles in
a)80.5 grams of K2IRCL6
b) 3.10 grams of calcium phosphate [K=39 , Ir =192 Ca=40 , P=31

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Answer 1

No. of moles = Given weight/Molecular mass

(a)

Given weight = 80.5g

Molecular mass of K2IrCl6

= k2 + Ir + Cl6

= (39 x 2) + 192 + (35.4 x 6)

= 78 + 192 + 212.4

= 482.4 u

No. of moles = 80.5/482.4 = 0.16 Moles.

(b)

Given weight = 3.10g

Molecular mass of Ca3(PO4)2

= Ca3 + (PO4)2

= (40 x 3) + (31 + 16 x 4)2

= 120 + 95 x 2

= 120 + 190

= 310 u

No. of moles = 3.10/310 = 0.01 Moles.