calculate the number of moles molecules and volume occupied by 6.4 g gas of oxygen at stp
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according to mole concept
moles =?
32g of oxygen contains 1 mole
6.4 g of 02 gas contains 1/32 (6.4)=0.2 moles similarly
32 g of oxygen contains 6.022 X 10²³ molecules
6.4 g of oxygen contains 1.2 x10²³ molecules
( check calculation)
volume =?
32 g of oxygen contains 22.4 litre's or 22400 cm3
now 6.4. g contains 22.4 X 0.2= 4.48 litre or 4480 cm³ or ml
hope u got it
moles =?
32g of oxygen contains 1 mole
6.4 g of 02 gas contains 1/32 (6.4)=0.2 moles similarly
32 g of oxygen contains 6.022 X 10²³ molecules
6.4 g of oxygen contains 1.2 x10²³ molecules
( check calculation)
volume =?
32 g of oxygen contains 22.4 litre's or 22400 cm3
now 6.4. g contains 22.4 X 0.2= 4.48 litre or 4480 cm³ or ml
hope u got it
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