Calculate the number of moles of ammonium sulfate present in 15.84 kg of it
Answers
Answered by
12
R. M. M of ammonium sulphate=
=2(14+4)+32+64
=36+32+64
=132 g
When mass of ammonium sulphate =132g
No. Of moles=1
When mass of ammonium sulphate = 15840g
No. Of moles=15840/132
= 120
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Answered by
7
Answer:
120 moles.
Explanation:
molecular weight of( Nh4)2 SO4
=(2×14)+(2×4)+32+(16×4)
132 a.m.u
132 g of (NH4)2 SO4 =1 mole
15.84 ×10 3(power 3 )g of
(NH4 )2 SO4=1by 132× 15.84×10 3(power 3)=120 mole
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