Question

Calculate the number of moles of butane c4h10 in 151g of butane (At. Masses c=12amu and h=1amu
(Ans:2.63moles

Answer 1

Answer:

gram atomic mass of butane = (12×4)+(1×10)g

=58 g

I gram atomic of substance contains 1 mole of that substance

=>151 g of butane =151/58 moles of butane =2.603 mol(ans)