Calculate the number of moles of NH3 formed by the reaction of 2 moles of N2 and 2 moles
of H2, N2(g) + 3H2(g) → 2NH3(g).
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Answer:
in the given reaction, 1 mole of n2 requires 3 moles of h2 for the formation of ammonia
thus if the number of mole of n2 and h2 should in 1:3 ratio
We know
n= molecular weight
thus the answer is :56 g of n2 means 2 moles of n2 and 10g of h2 means 5 moles of h2
here h2 acts as limiting reagent
Explanation:
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