Question

with the help of a suitable diagram prove that the reciprocal of the equivalent resistance of a group joined in parallel is equal to the sum of the reciprocal of the individual resistances​

Answer 1

Answer:

Since charge must be conserved, therefore the current I that enters at point ‘a’ must be equal to the current that leaves that point. Therefore we have I = I1 + I2 ...(i) Since the resistors are connected in parallel therefore the potential across each resistor must be same, hence by Ohm’s law we have substituting in equation (i) we have, Let RP be the equivalent resistance of the parallel combination, then by Ohm’s law we have, Hence from equations (ii) and (iii) we have, Read more on Sarthaks.com - https://www.sarthaks.com/340703/with-the-help-suitable-circuit-diagram-prove-that-the-reciprocal-equivalent-resistance

Explanation:

please follow me and vote me and like me

Answer 2

Answer:

ᴛʜᴇ ʀᴇᴄɪᴘʀᴏᴄᴀʟ ᴏғ ᴇǫᴜɪᴠᴀʟᴇɴᴛ ʀᴇsɪsᴛᴀɴᴄᴇ ᴏғ ᴀ ɢʀᴏᴜᴘ ᴏғ ʀᴇsɪsᴛᴀɴᴄᴇs ɪs ᴇǫᴜᴀʟ ᴛᴏ ᴛʜᴇ ᴊᴏɪɴᴇᴅ ɪɴ ᴘᴀʀᴀʟʟᴇʟ ɪs ᴇǫᴜᴀʟ ᴛᴏ sᴜᴍ ᴏғ ᴛʜᴇ ʀᴇᴄɪᴘʀᴏᴄᴀʟs ᴏғ ɪɴᴅɪᴠɪᴅᴜᴀʟs ʀᴇsɪsᴛᴀɴᴄᴇs.