Question

Calculate the number of moles of oxygen atoms comprising of 23 9.033 10

Answer 1

Answer:

Number of moles of oxygen is = 9.033*10^23/6.022*10^23= 1.5 moles

1 mole of oxygen = 16 gm

1.5 mole = 16*1.5 = 24gm

in water

O:H = 8:1

so mass of hydrogen will be

(24/3)*1 = 3 gm

mass of 1 mole of hydrogen = 1 gm

so we need 3 moles of hydrogen

in one mole of hydrogen we have = 6.022*10^23 atoms

in 3 moles = 6.022*10^23*3 = 18.066*10^23 atoms

total mass of water formed = 24+3 = 27 gms

Answer 2

Answer:

Number of moles of oxygen is = 9.033*10^23/6.022*10^23= 1.5 moles

1 mole of oxygen = 16 gm

1.5 mole = 16*1.5 = 24gm

in water

O:H = 8:1

so mass of hydrogen will be

(24/3)*1 = 3 gm

mass of 1 mole of hydrogen = 1 gm

so we need 3 moles of hydrogen

in one mole of hydrogen we have = 6.022*10^23 atoms

in 3 moles = 6.022*10^23*3 = 18.066*10^23 atoms

total mass of water formed = 24+3 = 27 gms