Question

Calculate the number of moles of sodium sulphite present in 6.3 g of sodium sulphite ​

Answer 1

Answer:

the number of moles of sodium sulphite present in 6.3 g of sodium sulphite is 0.05 moles

Explanation:

We first write down the molecular formula of Sodium Sulphite.

Formula: Na₂SO₃

From here, let's calculate the molar mass of Sodium Sulphite.

Na = 23

S = 32

O = 16

Molecular mass of the compound is given by:

= 23 × 2 + 32 + 16 × 3 = 126 grams per moles

The formula for getting the moles of a substance is given by:

Moles = Mass of substance / Molar mass

Substituting the values we have:

Moles = 6.3/126 = 0.05 moles.

Answer 2

$\large \tt no.of \: \: \: moles \: = 0 .05 \: \: moles$