Question

Calculate the number of moles present in 0.25g of calcium carbonate.

Answer 1

Answer:

25 g

0.25 moles of calcium carbonate (molecular weight 100 g/mole) corresponds to 25 g

Explanation:

weight of calcium carbonate given= 25 g. = 0.25 moles. thus number of moles in 25 g of calcium carbonate is 0.25.

Answer 2

100g CaCO3 = 1 mol
0.25 = (1/100) * 0.25 = 0.0025 mol