Question

Calculate the number of moles present in 1.51×10^23 molecules of ammonium chloride

Answer 1

6.022 × 10^23 molecules contain=1mole

1.51 × 10^23 molecules contain=1/6.022×10^23 × 1.51×10^23

= 0.25 moles

Answer 2

There are 0.251 moles of $NH_4Cl$

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {avogadro's number}}=\frac{1.51\times 10^{23}}{6.023\times 10^{23}}=0.251moles$

Thus there are 0.251 moles of $NH_4Cl$

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