Question

calculate the number of moles present in 18.066×10^21 atoms of SO2 ? ​

Answer 1

Explanation:

1 mole = 6.022 × 10^23

and

mass of SO2 will be

32+2(16)

= 32+32

= 64g

so

1 mole of SO2 atoms=gram atomic mass of SO2

=6.022 × 10^23

so

6.022 × 10^23 atoms of SO2 have mass 64g

18.066 × 10^21 have a mass of

=64/6.022×10^23 × 18.066×10^21

=1.92g

so

64g = 1 mole

1.92g = 1/64 × 1.92

= 0.03mole