Question

calculate the number of moles present in 32 grams of sulphur dioxide​

Answer 1

Answer:

moles=given mass÷molecular mass

moles= 32÷32

1 mole is required

Answer 2

Answer:

0.5 moles

Explanation:

Given :

32 g of Sulphur dioxide

To Find :

No. of Moles

Solution :

We know that molar mass of Sulphur Dioxide = 32+2 x 16 = 64

According to the definition of moles

No. of Moles present  = $\frac{\text{Amount (in grams)}}{\text{Moler Mass}}$

                                   = $\frac{32}{64}=\frac{1}{2}$

                                   = 0.5 moles

Hence we can say that  the number of moles present in 32 grams of Sulphur dioxide​ = 0.5 moles

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