Question

Calculate the number of moles present in 7.3g of HCL

Answer 1

molar mass of HCL = (1×1u) + (1×35.5 u)
=1+35.5
=36.5g
no.of moles = given mass ÷molar mass
=7.3g÷36.5g
=0.2g

Answer 2

mass numberof HCL =( 1×1)+ ( 1×35.5)
= 1+35.5
= 36.5