Calculate the number of moles, the number of molecules and the volume in cm3 of 0.32g of: 1)CH4 2)SO2 gases at STP
Answers
Explanation:
no. of moles of CH4= given weight/molecular weight
=0.32/16
=0.02 moles
no. of moles of SO2=given weight/molecular weight
=0.32/64
=0.005 moles
no. of molecules of CH4=moles*NA
=0.02*6.022*10²³
=0.12044*10²³
=1.2044*10²²
no. of molecules of SO2=moles*NA
=0.005*6.022*10²³
=0.030110*10²³
=3.0110*10²¹
volume at stp of CH4=moles*22.4
=0.02*22.4
=0.448dm³
=448cm³
volume at stp of SO2=moles*22.4
=0.005*22.4
=0.1120dm³
=112cm3
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